三条推文这么长的代码生成图片大赛
Kyle McCormick 在 StackExchange 上发起了一个叫做 Tweetable Mathematical Art 的比赛,参赛者需要用三条推文这么长的代码来生成一张图片。
1、首先是一个来自 Martin Büttner 的代码如下:
unsigned char RD(int i,int j){
return (char)(_sq(cos(atan2(j-512,i-512)/2))*255);
}
unsigned char GR(int i,int j){
return (char)(_sq(cos(atan2(j-512,i-512)/2-2*acos(-1)/3))*255);
}
unsigned char BL(int i,int j){
return (char)(_sq(cos(atan2(j-512,i-512)/2+2*acos(-1)/3))*255);
}
这段代码生成的作品:
2、在一段代码如下,目前暂时位列第一名:
unsigned char RD(int i,int j){
#define r(n)(rand()%n)
static char c[1024][1024];return!c[i][j]?c[i][j]=!r(999)?r(256):RD((i+r(2))%1024,(j+r(2))%1024):c[i][j];
}
unsigned char GR(int i,int j){
static char c[1024][1024];return!c[i][j]?c[i][j]=!r(999)?r(256):GR((i+r(2))%1024,(j+r(2))%1024):c[i][j];
}
unsigned char BL(int i,int j){
static char c[1024][1024];return!c[i][j]?c[i][j]=!r(999)?r(256):BL((i+r(2))%1024,(j+r(2))%1024):c[i][j];
}
这段代码生成的作品:
3、我个人认为这段代码比较牛:
unsigned char RD(int i,int j){
static double k;k+=rand()/1./RAND_MAX;int l=k;l%=512;return l>255?511-l:l;
}
unsigned char GR(int i,int j){
static double k;k+=rand()/1./RAND_MAX;int l=k;l%=512;return l>255?511-l:l;
}
unsigned char BL(int i,int j){
static double k;k+=rand()/1./RAND_MAX;int l=k;l%=512;return l>255?511-l:l;
}
这段代码生成的作品:
4、下面这段代码也非常棒:
unsigned char RD(int i,int j){
float s=3./(j+99);
float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;
return (int((i+DIM)*s+y)%2+int((DIM*2-i)*s+y)%2)*127;
}
unsigned char GR(int i,int j){
float s=3./(j+99);
float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;
return (int(5*((i+DIM)*s+y))%2+int(5*((DIM*2-i)*s+y))%2)*127;
}
unsigned char BL(int i,int j){
float s=3./(j+99);
float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;
return (int(29*((i+DIM)*s+y))%2+int(29*((DIM*2-i)*s+y))%2)*127;
}
它生成的作品让我想起了媳妇的衬衣:
文档信息
- 本文作者:Eric Chen
- 本文链接:https://aiwv.xyz/2015/06/14/one-code/
- 版权声明:自由转载-非商用-非衍生-保持署名(创意共享3.0许可证)